Solve for d 4-3d=d-8

$4 - 3 d = d - 8$

Move all terms containing $d$ to the left side of the equation.

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Subtract $d$ from both sides of the equation.

$4 - 3 d - d = - 8$

Subtract $d$ from $- 3 d$ .

$4 - 4 d = - 8$

Move all terms not containing $d$ to the right side of the equation.

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Subtract $4$ from both sides of the equation.

$- 4 d = - 8 - 4$

Subtract $4$ from $- 8$ .

$- 4 d = - 12$

Divide each term in $- 4 d = - 12$ by $- 4$ and simplify.

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Divide each term in $- 4 d = - 12$ by $- 4$ .

$\frac{- 4 d}{- 4} = \frac{- 12}{- 4}$

Simplify the left side.

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Cancel the common factor of $- 4$ .

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Cancel the common factor.

$\frac{- 4 d}{- 4} = \frac{- 12}{- 4}$

Divide $d$ by $1$ .

$d = \frac{- 12}{- 4}$

Simplify the right side.

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Divide $- 12$ by $- 4$ .

$d = 3$