Solve for c 3c+1=c+1

$3 c + 1 = c + 1$

Move all terms containing $c$ to the left side of the equation.

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Subtract $c$ from both sides of the equation.

$3 c + 1 - c = 1$

Subtract $c$ from $3 c$ .

$2 c + 1 = 1$

Move all terms not containing $c$ to the right side of the equation.

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Subtract $1$ from both sides of the equation.

$2 c = 1 - 1$

Subtract $1$ from $1$ .

$2 c = 0$

Divide each term in $2 c = 0$ by $2$ and simplify.

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Divide each term in $2 c = 0$ by $2$ .

$\frac{2 c}{2} = \frac{0}{2}$

Simplify the left side.

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Cancel the common factor of $2$ .

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Cancel the common factor.

$\frac{2 c}{2} = \frac{0}{2}$

Divide $c$ by $1$ .

$c = \frac{0}{2}$

Simplify the right side.

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Divide $0$ by $2$ .

$c = 0$